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0=-5x^2-11x+5
We move all terms to the left:
0-(-5x^2-11x+5)=0
We add all the numbers together, and all the variables
-(-5x^2-11x+5)=0
We get rid of parentheses
5x^2+11x-5=0
a = 5; b = 11; c = -5;
Δ = b2-4ac
Δ = 112-4·5·(-5)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{221}}{2*5}=\frac{-11-\sqrt{221}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{221}}{2*5}=\frac{-11+\sqrt{221}}{10} $
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